Examples of distributive property

We have created this article for you, so that you stop searching a large number of web pages without getting the answers you need, this article is dedicated to the functions of the distributive property and, simultaneously, the simplest examples of it so that together with us find out more about this interesting topic.

What is the distributive property?

We can define the distributive property as the multiplication property that is used in addition or subtraction operations, which reveals that two or more figures present in an operation, whether it is addition or subtraction, multiplied by another figure, derive equal to the subtraction or addition. of the multiplication of each of the figures.

“A number multiplied by the sum of two digits will give a result equal to the sum of each digit of the products of that number.”

What do we use this property for?

The distributive property is very useful as it helps us solve exercises in which a number is multiplied, either by addition or by subtraction.

This property is used to multiply a number by an addition or on the subtraction, being the multiplication on the addition.

However, it is also used to subtract the figures and then multiply them, we can also multiply them and then subtract them; this is commonly known as “the multiplier distribution”

Distributive Property Example

Now that you know more about the distributive property, we will provide you with a series of examples so that together with us you can discover the easiest way to execute it:

  1. 4 x (4 + 5) = 4 x 4 + 4 x 5
  2. 4 x 6 + 4 x 3 = 4 x (6 + 3)
  3. Ana is planning a birthday party for her sister, and she plans to share gum with all her friends. In order to distribute them, he will make bags in which he will put 5 mint gum, 4 strawberry gum and 3 watermelon gum and he will distribute only 10 bags of candy since he will not have many guests. How many candies will he distribute in total?

In order to solve this mathematical problem, we must know the amount of gum of each flavor that each bag contains and the number of existing bags. This means that it has two solutions, which we will explain below:

  • The first way is to find the total amount of gum that Ana placed in each bag and then multiply that amount by the number of bags:

5 + 4 + 3 = 12 gums in each bag

12 * 10 = 120 gums in total

  • The other way to solve this mathematical problem is to find the total amount of gum of each flavor and then add them, that is:

5 mint gum in 10 bags: 5 x 10 = 50 mint gum

4 strawberry gum in 10 bags: 4 x 10 = 40 strawberry gum

3 watermelon gum in 10 bags: 3 x 10 = 30 watermelon gum

Now we make the sum of all the chewing gums:

50 + 40 + 30 = 120 gums in total

We were able to observe that when performing the different processes we obtained the same result, this will be beneficial to you since this way you can execute the exercises in the way that is easiest for you to perform.

  1. 8x (13-1) = 8 × 13 – 8 × 1 = 8 x13 -8
  2. 2x (1 + 3) = 2 × 1 + 2 × 3 = 5
  3. 10x (5-2) = 10 × 5 – 10 × 2 = 30

We hope that our information on the distributive property and its examples has been helpful to you and we invite you to inquire more about it and other mathematical properties.

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